# SOLUTION: I don't know if I am on the right track or not , and I am not sure how to finish. 2 [1 -9] [0 -2 -8] - [1 10 6] [4 3] [4 7 5] - [5 -2 0] The brackets are to

Algebra ->  Algebra  -> Matrices-and-determiminant -> SOLUTION: I don't know if I am on the right track or not , and I am not sure how to finish. 2 [1 -9] [0 -2 -8] - [1 10 6] [4 3] [4 7 5] - [5 -2 0] The brackets are to       Log On

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 Question 73109: I don't know if I am on the right track or not , and I am not sure how to finish. 2 [1 -9] [0 -2 -8] - [1 10 6] [4 3] [4 7 5] - [5 -2 0] The brackets are to go around both rows (It is 2 times a 2by2 times a 2by3 subtract a 2by3 I have 2[-36 -65 -53] - [1 10 6] [ 12 13 -17] - [5 -2 0] I am not sure how to do the rest, do I multiply 2 by each # in the first 2x3? Please help.Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!2 [1 -9] [0 -2 -8] - [1 10 6] [4 3] [4 7 5] - [5 -2 0] The brackets are to go around both rows (It is 2 times a 2by2 times a 2by3 subtract a 2by3 I have 2[-36 -65 -53] - [1 10 6] [ 12 13 -17] - [5 -2 0] I am not sure how to do the rest, do I multiply 2 by each # in the first 2x3? Please help. --------------- Yes, multiply each element of the 2x3 matrix by 2 then subtract the corresponding elements of the last matrix -------- In the answer the element in the 1st row, 1st column is 2*-36-1=-73 ---------- Cheers, Stan H.