# SOLUTION: find an equation in the form y=ax^2+bx+c whose graph passes through the points (-1,-2), (1,4), (2,13)

Algebra ->  Algebra  -> Matrices-and-determiminant -> SOLUTION: find an equation in the form y=ax^2+bx+c whose graph passes through the points (-1,-2), (1,4), (2,13)      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Matrices, determinant, Cramer rule Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Matrices-and-determiminant Question 64639: find an equation in the form y=ax^2+bx+c whose graph passes through the points (-1,-2), (1,4), (2,13)Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!SEE THE FOLLOWING EXAMPLE AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK ------------------------------------ Find an equation of the form y = ax^2 + bx + c whose graph passes through the points (1,-2) (2,-1), and (3,4). SUBSTITUTING THE VALUE OF X FROM POINTS(X,Y) IN THE GIVEN EQN. FOR Y WE GET A+B+C=-2...................1 4A+2B+C=-1.......................2 9A+3B+C=4............3 EQN.2-EQN.1 3A+B=1................4 EQN.3-EQN.2 5A+B=5.................5 EQN.5 - EQN.4 2A=4 A=2 SUBSTITUTING IN EQN.4.... 6+B=1 B=-5 SUBSTITUTING IN EQN.1 2-5+C=-2 C=1 HENCE THE EQN.IS Y = 2X^2-5X+1