# SOLUTION: Hi! I think I got the correct answer to this word problem but am having trouble setting it up properly in a matrix (to get the right "output" answer). It is: when a crew rows with

Algebra ->  Algebra  -> Matrices-and-determiminant -> SOLUTION: Hi! I think I got the correct answer to this word problem but am having trouble setting it up properly in a matrix (to get the right "output" answer). It is: when a crew rows with       Log On

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 Question 604305: Hi! I think I got the correct answer to this word problem but am having trouble setting it up properly in a matrix (to get the right "output" answer). It is: when a crew rows with the current, it travels 16 miles in 2 hours. Against the current, the crew rows 8 miles in 2 hours. Let x=crew rowing rate in still water and y=rate of the current. I know rxt=d and x+y(t)=d and x-y(t)=d. I got x=6 and y=2. I have tried many different matrix "inputs" and just can't seem to get the right answer. I really wanted to figure it out on my own but am stuck. I know to line up the x's, y's, =k (constant). I need also to show the equation used.Thanks for any help!!!Answer by ankor@dixie-net.com(15660)   (Show Source): You can put this solution on YOUR website!a crew rows with the current, it travels 16 miles in 2 hours. Against the current, the crew rows 8 miles in 2 hours. Let x=crew rowing rate in still water and y=rate of the current. We know (x+y) = the effective speed downstream and (x-y) = effective speed upstream : Write a distance equation for each way 2(x+y) = 16 and 2(x-y) = 8 : You can simplify both equations by dividing thru by 2 x + y = 8 x - y = 4 -----------adding eliminates y, find x 2x = 12 x = 6 mph in still water then 6 + y = 8 y = 8 - 6 y = 2 is the rate of the current