SOLUTION: Is my answer correct? Suppose u, v and w are vectors in 3-space. Which are/is defined? A) (v.w) . u B) (w x u) x v My answer is only A is defined

Algebra.Com
Question 582471: Is my answer correct?
Suppose u, v and w are vectors in 3-space. Which are/is defined?
A) (v.w) . u

B) (w x u) x v

My answer is only A is defined

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
A)
This is NOT defined. The expression v.w results to be a scalar. Recall that the dot product a.b is only defined if BOTH a and b are vectors (of the same dimension). But since v.w is a scalar, the dot product isn't defined for z.u where z = v.w (because z is a scalar)

B)
This is defined. Both w and u are vectors in R3. So w x u is a vector in R3. If we let z = w x u, then (w x u) x v becomes z x v. So z is a vector in R3. The quantity v is a vector in R3.

This means that z x v is a vector in R3

Note: keep in mind that the cross product between vectors u and v is only defined if both u and v are vectors in R3 (3-space)

RELATED QUESTIONS

suppose u and V are vectors in 3 space. which is the true answer u.v is a scalar or... (answered by Fombitz)
Let u, v, and w be distinct vectors of a vector space V. Show that if {u, v, w} is a... (answered by khwang)
1)u×u>=0 and u×u=0 if and only if u=0 prove theorem? 2)Show that there are no vectors u... (answered by lynnlo)
Please help me ㅠㅠ help me 1)u×u>=0 and u×u=0 if and only if u=0 prove... (answered by lynnlo)
1)u×u>=0 and u×u=0 if and only if u=0 prove theorem? 2)Show that there are no vectors u... (answered by lynnlo)
Let u = (2,1,2), v = (3,2,1) and w = (1,2,-5) be vectors in 3-dimension space. (a).... (answered by Alan3354)
u: <3, -1> v: <4, 3> w: <⅔ , -8/9 > Which vectors involve right angles? A.) u... (answered by KMST)
Can anyone tell me if I'm on the right track with this: Question: Let G = (V, E) be a (answered by richard1234)
17. In each part, sketch the vector u + v+ w, and express it in component form.... (answered by stanbon,TipoTropical)