SOLUTION: Can you teach me how to solve this problem.
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the secon
Algebra.Com
Question 57787: Can you teach me how to solve this problem.
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers.
-----
Notice that the 1st and the 3rd are described in terms of the 2nd.
So. let the 2nd number be "x".
Then the 3rd is "10x-11"
Since 2(1st)=3x+7, 1st is (1/2)(3x+7)
EQUATION:
1st + 2nd + 3rd = 105
(1/2)(3x+7)+x+10x-11=105
(3/2)x+(7/2)+11x-11=105
(25/2)x=112.50
25x=225
x=9 (this is the 2nd number)
3rd number is 10x-11=79
1st number is (1/2)(3*9+7)=17
Cheers,
stan H.
RELATED QUESTIONS
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice... (answered by mananth)
the sum of three numbers is 105. the third is 11 less than ten times the second. twice... (answered by ankor@dixie-net.com)
Please help me solve this equation:
numeric word problem using 3 equations.
The... (answered by Mathtut,gonzo)
the sum ot three numbers is 105. the third is 11 less than ten times the second. twice... (answered by mathslover)
The sum of three numbers is 105. The third number is 11 less than 10 times the second... (answered by lwsshak3)
The sum of three numbers is 147. The second number is 4 more than two times the first... (answered by josmiceli,checkley77)
hi!
could you help me with this word problem.
thanks.
the sum of two numbers is... (answered by checkley71)
Word problem - The sum of two numbers is 15. Three times one of the numbers is 11 less... (answered by richwmiller)
How would you set this up? The second of three numbers is 6 times the first. The third is (answered by TimothyLamb)