SOLUTION: There were 510 people at a play. The admission price was 2 for adults and 1 for children. The admission receipts were 810. How many adults and how many children attended?

Question 567371: There were 510 people at a play. The admission price was 2 for adults and 1 for children. The admission receipts were 810. How many adults and how many children attended?
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
Adults = x
Children = 510-x
Total receipts = 810

Admission price for Adults = 2
Admission price for Children = 1

(Admission price for Adults)(Adults)+ (Admission price for Children)(Children) = Total receipts
(2)(x)+(1)(510-x)=810
2x+510-x=810
x=810-510
x=300

Adults = x = 300
Children = 510-x = 510-300 = 210

Check
======
300*2+210*1=810
600+210=810
810=810

RELATED QUESTIONS
there were 620 people at a play. The admission was $2 for adults and $1 for children. The (answered by josgarithmetic)

There were 360 people at a play. The admission price was $2 for adults and $1 for... (answered by ewatrrr)

There were 590 people at play. the admission price was $3.00 for adults and $1.00 for... (answered by Jstrasner)

Solve the problem. There were 420 people at a play. The admission price was $2 for adults (answered by lynnlo)

There were 610 people at a play. The admission price was 2$ for adults and 1$ for... (answered by chana)

There were 480 people at a play. The admission price was $2 for adults and $1 for... (answered by Alan3354)

There were 430 people at a play. The admission price was $3 for adults and $1 for... (answered by stanbon)

There were 460 people at a play. The admission price was $3 for adults and $1 for... (answered by Cromlix)

there were 619 people at a play. the admission price was 3$ for adults and $1 for... (answered by josgarithmetic)