SOLUTION: 3x-5y+4z=43
3x-2y-2z=10
x-y+3z=25
Algebra.Com
Question 564048: 3x-5y+4z=43
3x-2y-2z=10
x-y+3z=25
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3x-5y+4z=43
3x-2y-2z=10
x-y+3z=25
-----
Use any method you know to get:
x = 8
y = 1
z = 6
===========
Cheers,
Stan H.
=================
RELATED QUESTIONS
2x + 3z = 4
3y + 2z = 5
3x + 4y = −16
(x, y, z) =
2x +... (answered by Alan3354)
How to solve 3x+2y-3z= -2,... (answered by ewatrrr)
Solve:
x-6y-2z=-8
-x+5y+3z=2
3x-2y-4z=18
(answered by stanbon,addingup)
How do you solve:
5x+3y-2z=112
7x+5y=70
3x+y=9z+96
and
3w+3x+6y+5z=10... (answered by longjonsilver)
Solve the system of equations given: x+3z=12, -x-2y+z=10, 3x+5y+2z=-7 ... the answer in... (answered by Alan3354)
solve using the substitution method
problem 2x-y-z=15
4x+5y+2z=10
(answered by Edwin McCravy)
How do I solve:-5x+y-4z=60 How do I solve: -2x+5y+3z=-25
in variables... (answered by Alan3354)
Please help me solve this linear system with three variables.
2x-y+2z=-21
x+5y-z=25
(answered by Alan3354)
Solve by substituting
x + y + z = 8
-3x + 2y + 4z = 8
2x + 5y + 3z =... (answered by ankor@dixie-net.com)