# SOLUTION: In the school's chemistry lab, a certain acid is stored in two different dilutons. One bottle contains a weaker solution that is only 25% acid, but another has a stronger solution

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 Question 523181: In the school's chemistry lab, a certain acid is stored in two different dilutons. One bottle contains a weaker solution that is only 25% acid, but another has a stronger solution of 65% acid. students must pour some from each container to make 60ml of a solution that is 50% acid. HOw much from each container should be used? I know i'm going to use the two variables s-stronger and w-weaker. just can't figure out what the two equations going to be.Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website! In the school's chemistry lab, a certain acid is stored in two different dilutons. One bottle contains a weaker solution that is only 25% acid, but another has a stronger solution of 65% acid. students must pour some from each container to make 60ml of a solution that is 50% acid. HOw much from each container should be used? ----- Equations: Quantity: s + w = 60 ml Acid::::0.65s+0.25w = 0.50*60 -------------------------------------- Multiply thru the Quantity equation by 65 Multiply thru the Acid equation by 100 -------------------------------------------- 65s + 65w = 65*60 65s + 25w = 50*60 --------------------- subtract and solve for "w": 40w = 15*60 w = (3/2)15 w = 22.5 ml (amt. of weaker solution needed) ------ Solve for "s": s + w = 60 s = 60-22.5 = 37.5 ml ------------------------------ Cheers, Stan H. ===========================