Hi,

solution(s) for following system

x^2-y^2=4

y^2=3x 

x^2 - 3x - 4 = 0   

Yes! on the substitution resulting in x = -1 or x = 4 and y^2 = 12 Or y =  

(x = -1 is an extraneous solution as then Y^2 = -3 and y would then be an imaginary number.

Pt(4,) is the solution for this system of equations



 

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