SOLUTION: A mechanic has some 30% antifreeze solution and some 50% solution. How many liters of each should be used to get 50 liters of a 46% solution? Solve by using determinants. I'D

Algebra ->  Matrices-and-determiminant -> SOLUTION: A mechanic has some 30% antifreeze solution and some 50% solution. How many liters of each should be used to get 50 liters of a 46% solution? Solve by using determinants. I'D       Log On


   

Question 368336: A mechanic has some 30% antifreeze solution and some 50% solution. How many liters of each should be used to get 50 liters of a 46% solution? Solve by using determinants.

I'D REALLY APPRECIATE THE HELP!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x represent the total amount of the 50% solution.  

Then (50L - x) would be the amount of 30% solution

Question states***

.50x + .30(50L - x) = .46*50L

solving for x

.20x = .16*50L

x = 40L of the 50% solution and 10L of the 30% solution



checking our answer

20 + 3 = 23