SOLUTION: suppose A is a 3x3 matrix with elements
a11 =1 a12=0 a13=2
a21=-1 a22=3 a23=4
a31=0 a32=1 a33=0
how would you use A^-1 to find the solutions of the linear system
x+2z = 1 and
Algebra.Com
Question 350586: suppose A is a 3x3 matrix with elements
a11 =1 a12=0 a13=2
a21=-1 a22=3 a23=4
a31=0 a32=1 a33=0
how would you use A^-1 to find the solutions of the linear system
x+2z = 1 and -x+3y+4z =2 and y=3
could you please show working.
i have used numbers with subscripts to depict the matrix entries because i dont know how to type the brackets
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
[A]=
.
.
.
[A][x]=[b]
.
.
where,
[x]=
[b]=
.
.
.
[A][x]=[b]
.
.
[A]inv[A][x]=[A]inv[b]
.
.
Since [A]inv[A]=[I], then
.
.
[x]=[A]inv[b]
.
.
.
det[A]=
.
.
.
[A]inv=
*([A]inv[b])=
*([A]inv[b])=
Then,
[x]=
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