SOLUTION: The value of square-root(2/pi) * Integral(e to the power -square(t)/2 ), where "t" is a variable from 4 to infinity is equal to what?

Question 30044: The value of square-root(2/pi) * Integral(e to the power -square(t)/2 ),
where "t" is a variable from 4 to infinity is equal to what?

Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
The value of square-root(2/pi) * Integral(e to the power -square(t)/2 ),
where "t" is a variable from 4 to infinity is equal to what?
THIS IS CALLED PROBABILITY INTEGRAL FOR WHICH YOU HAVE TO REFER STANDARD TABLES
THE TABLE IS MADE FOR
P(T)=(1/SQRT(2PI))*INTEGRAL{0 TO T OF (E^(-T^2/2) DT)}
IT IS THE AREA UNDER THE CURVE.PRACTICALLY,THE ENTIRE CURVE LIES BETWEEN
T=- 3AND +3...99.73% IN FACT..SO IF YOU WANT AREA BEYOND T=4 IT IS ALMOST ZERO..THE ANSWER IS NEARLY ZERO.
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