You can
put this solution on YOUR website!A neat way of doing this is as follows: write the first two columns again on the right and draw a line down the first three forward diagonals:
3 3 4 3 3
\ \ \
6 1 2 6 1
\ \ \
3 2 2 3 2
Multiply down each diagonal and add them up: 6 + 18 + 48 = 72
Now do the same with the last three backward diagonals:
3 3 4 3 3
/ / /
6 1 2 6 1
/ / /
3 2 2 3 2
You get 12 + 12 + 36 = 60
The determinant is the first (72) minus the second (60), giving 12.
For a square matrix of size n, you repeat the first (n-1) columns and use the first and last n diagonals.