SOLUTION:
x+y+z=30
x+2y+z=$7.46
2.49x+1.99y+.99z=$70.00
Algebra.Com
Question 250960:
x+y+z=30
x+2y+z=$7.46
2.49x+1.99y+.99z=$70.00
Answer by MRperkins(300) (Show Source): You can put this solution on YOUR website!
I have a very similar problem already worked out and scanned as a .PDF file. If you will email me, then I will send you the .pdf file and we can also work the problem in an online whiteboard. My email is justin.sheppard.tech@hotmail.com
RELATED QUESTIONS
solve using cramer rule :- 3x+2y+4z=19 2x-y+z=3 6x+7y-z=7
x-y+z= 1 x+y+z=2 2x-y+z=5... (answered by ikleyn)
{x-y+2z=-7
{y+z=1
{x=2y+3z
(answered by erica65404)
solve using cramer rule :- 3x+2y+4z=19 2x-y+z=3 6x+7y-z=7
x-y+2z=1 x+y+z=2 2x-y+z=5... (answered by ikleyn)
x − 2y + z = 4
y + 6z =-1
z =... (answered by Fombitz)
x-y+z=-8
4x+2y-z=7... (answered by ikleyn)
solve system of equation.
x+2y+z=4
2x+y-z=-1... (answered by jim_thompson5910)
y=2(x-3z)x=2y=-3and... (answered by nyc_function)
solve the system
x-y+z=-4
x+2y-z=-2... (answered by Fombitz)
Solve each of these system of equations.
1) x + 2y + z = 10
2x - y + 3z = -5
(answered by Alan3354)