SOLUTION: using elimination how do u find (x,y and z) using these 3 equations?
3x+2y-z=-1
x+3y-z=-10
2x-y-3z=3
Algebra.Com
Question 224074: using elimination how do u find (x,y and z) using these 3 equations?
3x+2y-z=-1
x+3y-z=-10
2x-y-3z=3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
using elimination how do u find (x,y and z) using these 3 equations?
3x+2y-z=-1
x+3y-z=-10
2x-y-3z=3
-------------------
Let the 2nd equation be the 1st:
x+3y-z=-10
3x+2y-z=-1
2x-y-3z=3
-------------------
Subtract 3 times 1st from 2nd:
Subtract 2 times 1st from 3rd:
x+3y-z=-10
0x-7y+2Z=29
0x-7y-z=23
------------------
Subtract 2nd from 3rd:
x+3y-z=-10
0x-7y+2Z=29
0x+0y-3z=-6
----------------
Solve the 3rd equation to get z = 2
---
Substitute that into the 2nd to get:
-7y+4 = 29
-7y = 25
y = -25/7
-----------------
Substitute those into the 1st to get:
x = 19/7
======================
Cheers,
Stan H.
RELATED QUESTIONS
How do you solve these 3 linear equations using elimination method
2x-3y+z=13
x+y-2z=-6
(answered by Edwin McCravy,MathTherapy)
Using Gauss-Jordan elimination- solve following system of equations.
x+y+z=2... (answered by venugopalramana)
How do I solve this system using elimination?
-2x+2y+3z=0
-2x-y+z=-3... (answered by Alan3354)
How do I solve this system using elimination?
-2x+2y+3z=0
-2x-y+z=-3... (answered by Alan3354)
How do I solve this system using elimination?
-2x+2y+3z=0
-2x-y+z=-3... (answered by josgarithmetic)
-3x+3y–3z=6
-x+y+z= -10
-x–3y–z=-14
solve a system of equations in 3 variables using (answered by stanbon)
Solve each of these system of equations.
1) x + 2y + z = 10
2x - y + 3z = -5
(answered by Alan3354)
How do you solve this system of three linear equations using elimination method... (answered by math_tutor2020,MathLover1)
find the ordered triple of these equations
x-2y+3z=-3
2x-3y-z=7... (answered by richwmiller)