SOLUTION: the square of the sum of two numbers equals the sum of their squares plus twice their product

Question 189314: the square of the sum of two numbers equals the sum of their squares plus twice their product
Found 2 solutions by checkley75, J2R2R:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
(x+y)^2=x^2+y^2+2xy
x^2+2xy+y^2=x^2+2xy+y^2 proof.
Answer by J2R2R(94) (Show Source): You can put this solution on YOUR website!
The square of the sum of two numbers equals the sum of their squares plus twice their product.

This should be obvious as it is applied to all values � it doesn�t have any specific solutions.

The square of the sum of two numbers: (x + y)^2; equals the sum of their squares plus twice their product: x^2 + y^2 + 2xy.

Well, (x + y)^2 = x^2 + y^2 + 2xy for all values of x and y, so it is like saying two times the number equals the number times two, which applies to all numbers.

So the question is nothing more than a statement of what expanding the expression (x + y) to the second power gives.
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