SOLUTION: please solve each matriz.. 1. [3 4] [3] [-1 -1]x=[2] 2. [6 2] [8 1] [-1 4]-x [1 3] 3. x+[1 3 6] [8 1 0] [-1 2 1]= [14 3 -1]

Algebra ->  Matrices-and-determiminant -> SOLUTION: please solve each matriz.. 1. [3 4] [3] [-1 -1]x=[2] 2. [6 2] [8 1] [-1 4]-x [1 3] 3. x+[1 3 6] [8 1 0] [-1 2 1]= [14 3 -1]       Log On


   

Question 177938: please solve each matriz..

1. [3 4] [3]
[-1 -1]x=[2]



2. [6 2] [8 1]
[-1 4]-x [1 3]




3. x+[1 3 6] [8 1 0]
[-1 2 1]= [14 3 -1]



4. [-3 -2] [8 -1]
[1 1] x=[6 0]



5. 4x+3 [3 2] [10 8]
[1 -2]= [5 -2]



6. 2x=1/4[-6 2]
[8 -8]
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!

I will do a few and let you do the rest
:
1. [3 4] [3]
[-1 -1]x=[2]
:
This is done with the assumption that you know how to multiply,add,and subtract matrices.
:
in this problem we have a 2x2 multiplied by a 2x1 and we of course get a 2x1 answer.
:
lets call our unknown matrix x= %28matrix%282%2C1%2Ca%2Cb%29%29
so
:
%28matrix%282%2C2%2C3%2C4%2C-1%2C-1%29%29 %28matrix%282%2C1%2Ca%2Cb%29%29= %28matrix%282%2C1%2C3%2C2%29%29
:
3a-4b=3.....eq 1
-1a+b=2.....eq 2
:
so now we have a set of linear equations to solve
multiply eq 2 by 3 and add the two equations together. a terms will be eliminated because 3a-3a=0. We are left with -4b+3b=9
:
-b=9
:
b=-9
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now plug this value into either eq
:
-1a+(-9))=2--->-a=2+9--->a=-11
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so x=%28matrix%282%2C1%2C-11%2C-9%29%29
:
3. x+[1 3 6] [8 1 0]
[-1 2 1]= [14 3 -1]
lets call x=%28matrix%282%2C3%2Ca%2Cb%2Cc%2Cd%2Ce%2Cf%29%29
:
so %28matrix%282%2C3%2Ca%2Cb%2Cc%2Cd%2Ce%2Cf%29%29+%28matrix%282%2C3%2C1%2C3%2C6%2C-1%2C2%2C1%29%29=%28matrix%282%2C3%2C8%2C1%2C0%2C14%2C3%2C-1%29%29
:
a+1=8--->a=7
b+3=1--->b=-2
c+6=0--->c=-6
d-1=14-->d=15
e+2=3--->e=1
f+1=-1-->f=-2
:
x=%28matrix%282%2C3%2C7%2C-2%2C-6%2C15%2C1%2C-2%29%29
:
hope that helps you on your way