SOLUTION: How do I find B-CF? B= [2,8,.6,3] C=[12,0,1.5,1,-6,7] F=[-2,0,0,8,2,1]

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Question 175431: How do I find B-CF?
B= [2,8,.6,3] C=[12,0,1.5,1,-6,7] F=[-2,0,0,8,2,1]
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
I'm guessing on the make up of the matrices.
First off let's look at [C][F].
[C]=
[F]=
[C][F]=
where each element of [C][F] comes from multiplying a row of [C] with a column of [F].
Example: First element is product of first row and first column.

.
.
.
Now that we have [C][F], we can subtract it from [B], element by element,
[B]-[C][F]=
[B]-[C][F]=
.
.
.
If this is not how the matrices look,please re-state the problem and be more specific about the make up of the matrices (rows x columns).
Here's an example.
[A] is a 2x2 matrix. A=[1,2,3,4].
The assumption is that [A] looks like this,
[A]=
[B] is a 3x2 matrix. B=[5,6,7,8,9,10]
[B]=

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