SOLUTION: Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation. <p> </p> {(2/3)x + (1/5)y = 3 {(3/2)x + (5/3)y = (2/3) <p> </p> If i

Algebra ->  Algebra  -> Matrices-and-determiminant -> SOLUTION: Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation. <p> </p> {(2/3)x + (1/5)y = 3 {(3/2)x + (5/3)y = (2/3) <p> </p> If i      Log On

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Question 162222: Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation.


{(2/3)x + (1/5)y = 3
{(3/2)x + (5/3)y = (2/3)


If it makes it any easier, our teacher said we can also use subtitution and elimination method.
Answer by stanbon(57246) About Me  (Show Source):
You can put this solution on YOUR website!
Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation.
{(2/3)x + (1/5)y = 3
{(3/2)x + (5/3)y = (2/3)
If it makes it any easier, our teacher said we can also use subtitution and elimination method.
--------------------
The fact that you have fractions does not make any difference in
using Cramer's Method.
But you can get rid of the fractions:
Multiply thru the 1st equation by 15 to get:
10x + 3y = 45
Multiply thru the 2nd equation by 6 to get:
9x + 10y = 4
------------------
Now, use Cramer or elimination to get:
x = 6
y = -5
==========
Cheers,
Stan H.