# SOLUTION: Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation. <p> </p> {(2/3)x + (1/5)y = 3 {(3/2)x + (5/3)y = (2/3) <p> </p> If i

Algebra ->  Algebra  -> Matrices-and-determiminant -> SOLUTION: Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation. <p> </p> {(2/3)x + (1/5)y = 3 {(3/2)x + (5/3)y = (2/3) <p> </p> If i      Log On

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 Algebra: Matrices, determinant, Cramer rule Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Matrices-and-determiminant Question 162222: Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation. {(2/3)x + (1/5)y = 3 {(3/2)x + (5/3)y = (2/3) If it makes it any easier, our teacher said we can also use subtitution and elimination method. Answer by stanbon(57246)   (Show Source): You can put this solution on YOUR website!Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation. {(2/3)x + (1/5)y = 3 {(3/2)x + (5/3)y = (2/3) If it makes it any easier, our teacher said we can also use subtitution and elimination method. -------------------- The fact that you have fractions does not make any difference in using Cramer's Method. But you can get rid of the fractions: Multiply thru the 1st equation by 15 to get: 10x + 3y = 45 Multiply thru the 2nd equation by 6 to get: 9x + 10y = 4 ------------------ Now, use Cramer or elimination to get: x = 6 y = -5 ========== Cheers, Stan H.