SOLUTION: PROBLEM:
SOLVE THE EQUATION BY COMPLETING THE SQUARE AND APPLYING THE SQUARE ROOT PROPERTY.
4y^2-12y+13=0
THIS PROBELM IS VERY DIFFICULT FOR ME TO UNDERSTAND I KNOW THIS MUCH SO
Algebra.Com
Question 138827: PROBLEM:
SOLVE THE EQUATION BY COMPLETING THE SQUARE AND APPLYING THE SQUARE ROOT PROPERTY.
4y^2-12y+13=0
THIS PROBELM IS VERY DIFFICULT FOR ME TO UNDERSTAND I KNOW THIS MUCH SO FAR BUT I GET STUCK CAN YOU PLEASE HELP!!
4y^2-12y=-13
4y^2-12y+(-12/2)^2=-13+(-12-2)^2
this is as far as i can get please help
Found 2 solutions by vleith, stanbon:
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
=
You are given
In this equation, a is 2 (since 4 = 2^2)
And = =
and
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
4y^2-12y+13=0
4y^2 - 12y = -13
4(y^2 - 3y + ?) = -13 + 4*?
4(y^2-3y+(3/2)^2) = -13 + 4*(3/2)^2
4(y - (3/2))^2 = -13 +9
Divide both sides by 4 to get:
(y-(3/2))^2 = -1
Take the square root of both sides to get:
y-(3/2) = +/- i
y = [(3/2) + i] or y = [(3/2) - i]
====================
Cheers,
Stan H.
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