# SOLUTION: The length of fence required to enclose a rectangular field is 3000 meters. What are the dimensions of the field if the difference between its length and width is 50 meters?

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 Click here to see ALL problems on Matrices-and-determiminant Question 122309This question is from textbook Finite Mathematics an Applied Approach : The length of fence required to enclose a rectangular field is 3000 meters. What are the dimensions of the field if the difference between its length and width is 50 meters?This question is from textbook Finite Mathematics an Applied Approach Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!2x+2(x+50)=3000 2x+2x+100=3000 4x=3000-100 4x=2900 x=2900/4 x=725 for the length. x+50=775 for the width. proof 2*725+2*775=3000 1450+1550=3000 3000=3000