SOLUTION: The length of fence required to enclose a rectangular field is 3000 meters. What are the dimensions of the field if the difference between its length and width is 50 meters?
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Question 122309This question is from textbook Finite Mathematics an Applied Approach
: The length of fence required to enclose a rectangular field is 3000 meters. What are the dimensions of the field if the difference between its length and width is 50 meters?
This question is from textbook Finite Mathematics an Applied Approach
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
2x+2(x+50)=3000
2x+2x+100=3000
4x=3000-100
4x=2900
x=2900/4
x=725 for the length.
x+50=775 for the width.
proof
2*725+2*775=3000
1450+1550=3000
3000=3000
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