SOLUTION: DENTAL FILLINGS Dentists use various amalgams for silver fillings. The matrix shows the percent's (expressed as decimals) of powdered alloys used in preparing three different amalg

Algebra.Com
Question 1189235: DENTAL FILLINGS Dentists use various amalgams for silver fillings. The matrix shows the percent's (expressed as decimals) of powdered alloys used in preparing three different amalgams. Suppose a dentist has 5483 grams of silver, 2009 grams of tin, and 129 grams of copper. How much of each amalgam can be made?
PERCENT ALLOY BY WEIGHT
Amalgam
A
B
Silver
Tin
0.70
| 0.26
0.04
matrix 2&0.73\\ 5&0.27\\ 3&0.00 matrix ]
Copper

Answer by josgarithmetic(39632)   (Show Source): You can put this solution on YOUR website!
Very bad tabular formatting!!

Maybe some chance a duplication with an included picture is at this link:
https://www.numerade.com/ask/question/question-2-dentists-use-various-amalgams-for-silver-fillings-the-matrix-shows-the-percentages-expressed-as-decimals-of-powdered-alloys-used-in-preparing-three-different-amalgams-suppose-dent-69835/

RELATED QUESTIONS

One of the first mixtures of metals, called amalgams, used by dentists for tooth fillings (answered by nerdybill)
Each person in the class has three choices of burrito meat fillings (chicken, beef, or... (answered by stanbon)
A jeweler has 3 rings, each weighing 15 g, made of an alloy of 25 percent silver and 75... (answered by josgarithmetic)
Shaver Manufacturing, Inc. offers dental insurance to its employees. A recent study by... (answered by Theo)
Shaver Manufacturing, Inc., offers dental insurance to its employees. A recent study by... (answered by stanbon)
Daphne had lunch at a sandwich shop. She could choose one of the following breads:... (answered by rfer)
2. (a) Prove that the product of a matrix and its transpose is symmetric matrix (b)... (answered by lynnlo)
1. (O+M)>S 2. ~S /~M Use the eighteen inference rules to construct proofs for the... (answered by Edwin McCravy)
Michelle buys a rug for $36 and sells it for $90 what was the value of her markup... (answered by checkley79)