SOLUTION: Given the matric A= -1 3 find A^3 0 2 I cannot figure out what I did wrong. 1*-1+3*0+-1*3+3*2 -1*-1+3*0+-1*3+3*2 = 1 3 0*-1+2*0+2*3+2*2 0-*1+

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Question 1175799: Given the matric A= -1 3 find A^3
0 2
I cannot figure out what I did wrong.
1*-1+3*0+-1*3+3*2 -1*-1+3*0+-1*3+3*2 = 1 3
0*-1+2*0+2*3+2*2 0-*1+2*0+2*3+2*2 0 10
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52858)   (Show Source): You can put this solution on YOUR website!
.

You SHOULD calculate it in two steps. 

    First calculate   =  . .


    Then calculate   =  . .


Do not try to unite these two steps into one.



Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Given the matric A= -1 3 find A^3
0 2
------------
A*A = B
|-1 3|  |-1 3|   |a b|
| 0 2|* | 0 2| = |c d|
---
a = -1*-1+3*0 = 1
b = -1*3+3*2 = 3
c = 0*-1+2*0 = 0
d = 0*3+2*2 = 4
----
B = |1 3|
    |0 4|
--------------
A*B = |-1 3| |1 3|   |e f|
      | 0 2|*|0 4| = |g h|
----
e = -1*1+3*0 = -1
f = -1*3+3*4 = 9
g = 0*1+2*0 = 0
h = 0*3+2*4 = 8
----
|-1 9|
| 0 8| = A^3

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