SOLUTION: For the system of equations : x+2y+3z=73 3x+y+z=49 2x+3y+4z=106 In matrix form AX=B,the inverse matrix A^-1 is A^-1 = 1/2 [ 1 1 -1

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Question 1174243: For the system of equations :
x+2y+3z=73
3x+y+z=49
2x+3y+4z=106
In matrix form AX=B,the inverse matrix A^-1 is A^-1 = 1/2 [ 1 1 -1
-10 -2 8
7 1 -5 ]
Use A^-1 to solve the system. Show all work.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi










   * =

Note:
   (1)73 + (1)49 + (-1) 106 = 16
  -730  - 98 + (8)106 = 20  
   (7)73 + 49 + (-5)106= 30


 (1/2)  = 

   (8,10,15)  the solution for this system of Equations


Wish You the Best in your Studies.





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