N=10a+b
Given:
a + b = 12 (1)
and "digits reversed decreases # by 18" tell us:
10b + a = (10a+b)-18
which simplifies to
-9a + 9b = -18 (2)
multiply (1) by 9 and add to (2) to get:
9a + 9b = 108
-9a + 9b = -18
-----------------
18b = 90 --> b=5 --> a=7 -->
Check:
7+ 5 = 12 (ok on sum of digits)
75 - 18 = 57 (ok on digits reversed)