SOLUTION: Evaluate the determinant, using row or column operations whenever possible to simplify your work. [0 0 4 6] [2 1 1 3] [2 1 2 3] [3 0 1 7]

Question 1129413: Evaluate the determinant, using row or column operations whenever possible to simplify your work.
[0 0 4 6]
[2 1 1 3]
[2 1 2 3]
[3 0 1 7]

Found 2 solutions by t0hierry, Alan3354:
Answer by t0hierry(194) (Show Source): You can put this solution on YOUR website!

[0 0 4 6]
[2 1 1 3]
[2 1 2 3]
[3 0 1 7]
We start from the first row and we get:
4* [2 1 3]
[2 1 3]
[3 0 7]
6* [2 1 1]
[2 1 2]
[3 0 1]
again from last row for the first term
3*0 + 7*0 = 0
same for the second term
3*1 + 0 = 3
Now for the sign: it's minus
so I find -3.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Evaluate the determinant, using row or column operations whenever possible to simplify your work.
[0 0 4 6]
[2 1 1 3]
[2 1 2 3]
[3 0 1 7]
---------------
Row 1 has 2 zeroes, makes it easy.
----
4 times

|2 1 3| |2 1 3| |3 0 7| 2 equal rows --> 0 4*0 = 0 ======================== -6 times |2 1 1| |2 1 2| |3 0 1| = -6*(2*(1-0) - 1*(2-6) + 1*(0-3)) = -6*(2 + 4 - 3) = -18

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