SOLUTION: 3x+4y+5z=18,2x-y+8z=13,5x-2y+7z=20
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Question 1126612: 3x+4y+5z=18,2x-y+8z=13,5x-2y+7z=20
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Not a complete solution - just a possible way to use few steps -
4*E2+E1 to eliminate y
and
-2E2+E3 to eliminate y
E1-E2 to eliminate z
-------one of the variables now found.
Use either equation from previous system to get y and z.
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