SOLUTION: Find the values of k for which the given linear system is consistent x-3y+z=1 2x-2y =k^2 3x-5y+z=0 -2x+8y+4=49

Question 1121132: Find the values of k for which the given linear system is consistent
x-3y+z=1
2x-2y =k^2
3x-5y+z=0
-2x+8y+4=49
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find the values of k for which the given linear system is consistent
x-3y+z=1
2x-2y =k^2
3x-5y+z=0
-2x+8y+4=49
:
Use elimination on the 1st and 3rd equation
3x- 5y + z = 0
x - 3y + z = 1
-------------------Subtraction eliminate z
2x - 2y = -1
:
Use elimination again with this equation and the 4th equation (simplified)
2x - 2y = -1
-2x +8y = 45
--------------Addition eliminates x, find y
0 + 6y = 44
y = 44/6
y = 7.33
:
find x
2x - 2(7.33) = -1
2x - 14.66 = -1
2x = -1 + 14.66
2x = 13.66
x = 13.66/2
x = 6.83
:
Find the value of K using the 2nd equation
2(6.83) - 2(7.33) = k^2
13.66 - 14.66 = k^2
k^2 = -1
k =
k = i

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