SOLUTION: My doubt is show that in matrix [1 a a^2-bc] [1 b b^2-ac] = 0.

Question 1119679: My doubt is show that in matrix [1 a a^2-bc]
[1 b b^2-ac] = 0.
[1 c c^2-ab]
Answer by ikleyn(52835) (Show Source): You can put this solution on YOUR website!
.
My doubt is show that in matrix [1 a a^2-bc]
[1 b b^2-ac] = 0.
[1 c c^2-ab]
~~~~~~~~~~~~~~~~~~~

Based on your post, I only can guess what do you need.

If you need to calculate the determinant, apply co-factoring the determinant along the first column.

See the lesson
- Co-factoring the determinant of a 3x3 matrix
in this site, where co-factoring along the first row was described.

Co-factoring along the first column works in the same way.

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