solve for x if [3 1 0
2 x 1
4 5 -2] = 0
--------------------------
|3 1 0|
|2 x 1| = 0
|4 5 -2|
===============
|2 x 1|
|3 1 0| = 0
|4 5 -2|
=================
|x 2 1|
|1 3 0| = 0
|5 4 -2|
---------
x*(-6-0) - 2*(-1-0) + 1*(4-15) = 0
-6x + 2 - 11 = 0
-6x = 9
x = -3/2
------------------------
the transposing is not necessary, but it gives just one term with x.