create a list as shown below:
buffet chair table total
cutting 15 5 10 4900
assembly 20 8 6 6600
finishing 5 5 6 3900
if you let:
x = number of buffets
y = number of chairs
z = number of tables
then your 3 equations that need to be solved simultaneously are:
15x + 5y + 10z = 4900 (equation 1)
20x + 8y + 6z = 6600 (equation 2)
5x + 5y + 6z = 3900 (equation 3)
multiply equation 1 by 3 and equation 2 by 5 to get:
45x + 15y + 30z = 14700 (equation 4)
100x + 40y + 30z = 33000 (equation 5)
subtract equation 4 from equation 5 to get:
55x + 25y = 18300 (equation 6)
leave equation 2 equation 3 as is to get:
20x + 8y + 6z = 6600 (equation 2)
5x + 5y + 6z = 3900 (equation 3)
subtract equation 3 from equation 2 to get:
15x + 3y = 2700 (equation 7)
bring down equation 6 and equation 7.
55x + 25y = 18300 (equation 6)
15x + 3y = 2700 (equation 7)
multiply equation 6 by 3 and 7 by 25 to get:
165x + 75y = 54900 (equation 8)
375x + 75y = 67500 (equation 9)
subtract equation 8 from equation 9 to get:
210x = 12600
solve for x to get x = 12600 / 210 = 60
go back to either equation 6 or equation 7 and solve for y when x 60 to get:
y = 600.
go back to either equation 1 or 2 or 3 and solve for z when x = 60 and y = 600 to get:
z = 100
your solution to all 3 original equations should be:
x = 60
y = 600
z = 100
when x = 60 and y = 600 and z = 100:
15x + 5y + 10z = 4900 (equation 1) becomes 4900 = 4900 which is true.
20x + 8y + 6z = 6600 (equation 2) becomes 6600 = 6600 which is true.
5x + 5y + 6z = 3900 (equation 3) becomes 3900 = 3900 which is true.
the solution is confirmed to be good.
the solution is:
full utilization of resources is satisfied when 60 buffets and 600 chairs and 100 tables are built.