SOLUTION: 2x-y+z=0
x+3y+2z=16
3x-y+z=3
Algebra.Com
Question 1080680: 2x-y+z=0
x+3y+2z=16
3x-y+z=3
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use Cramer's rule,
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