SOLUTION: Solve the equation on the interval [0, 2pi). tan^2 x sin x = tan^2 x B.pi/2 , pi D. 0, pi

Question 1074774: Solve the equation on the interval [0, 2pi).
tan^2 x sin x = tan^2 x
B.pi/2 , pi
D. 0, pi
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Solve the equation on the interval [0, 2pi).
tan^2 x sin x = tan^2 x
B.pi/2 , pi
D. 0, pi
~~~~~~~~~~~~~~~~~~~~

 =   --->

 = 0.


This equation deploys in two independent equations:


1.  tan(x) = 0 with the solutions x = 0 and/or x = .


2.  sin(x) = 1 with the solution  x = .

    This solution is EXTRANEOUS, since  tan is not defined for x = .


Answer.  The solutions are  x = 0  and  x = .

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