# SOLUTION: An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air.

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 Click here to see ALL problems on Matrices-and-determiminant Question 105148: An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air. Answer by ankor@dixie-net.com(15746)   (Show Source): You can put this solution on YOUR website!An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air. : Let s = speed in still air : (s+25) = speed with wind (s-25) = speed against the wind : The trip out and the trip back are equal distance. Write a distance equation. Distance = time * speed : 5(s-25) = 4(s+25) 5s - 125 = 4s + 100 5s - 4s = 100 + 125 s = 225 mph in still air : : Check the solution by finding the distances to be equal: Against: 5(200) = 1000 mi With: 4(250) = 1000 mi confirms our solution