Questions on Algebra: Matrices, determinant, Cramer rule answered by real tutors!

Algebra ->  Algebra -> Questions on Algebra: Matrices, determinant, Cramer rule answered by real tutors!     (Log On)
Ad: Algebra Solved!™: algebra software that solves YOUR algebra homework problems with step-by-step help!



Question 162093: I am completely lost on this worksheet and have no book. Please help.
Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation.
Thanks
: I am completely lost on this worksheet and have no book. Please help.
Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation.
Thanks

Answer by elima(1427) About Me  (Show Source):
You can put this solution on YOUR website!
9x^2+1=6x
First let's but this in standard form;
9x^2-6x+1=0
discriminant;
b^2-4ac
a=9
b=-6
c=1
Now we plug these in;
-6^2-4(9)(1)
36-36=0
Since the discriminant is 0, there is one real root.
Now use the discriminant in the quadratic equation to find the number;
(-6+-sqrt(0))/2(9)
-6/18 = 1/3
If the discriminant is negative, there are no real roots;
If the discriminant is positive, there are two real roots.
:)