You can
put this solution on YOUR website!Note:
![CR[1]](/cgi-bin/plot-formula.mpl?expression=CR%5B1%5D&x=0003)
= 1st chem. rxn
![CR[2]](/cgi-bin/plot-formula.mpl?expression=CR%5B2%5D&x=0003)
= 2nd chem. rxn
![CR[3]](/cgi-bin/plot-formula.mpl?expression=CR%5B3%5D&x=0003)
= 3rd chem. rxn.
![O[2]](/cgi-bin/plot-formula.mpl?expression=O%5B2%5D&x=0003)
= Oxygen produced by each rxn.
1st condition:
![CR[1]](/cgi-bin/plot-formula.mpl?expression=CR%5B1%5D&x=0003)
produces twice that of
![CR[2]](/cgi-bin/plot-formula.mpl?expression=CR%5B2%5D&x=0003)
-------->
![CR[1]=2O[2]](/cgi-bin/plot-formula.mpl?expression=CR%5B1%5D=2O%5B2%5D&x=0003)
-------->
![CR[2]= O[2]](/cgi-bin/plot-formula.mpl?expression=CR%5B2%5D=+O%5B2%5D&x=0003)
2nd condition:
![CR[3]](/cgi-bin/plot-formula.mpl?expression=CR%5B3%5D&x=0003)
produces twice that of
![CR[1]](/cgi-bin/plot-formula.mpl?expression=CR%5B1%5D&x=0003)
-------->
![CR[3]=2(2O[2])](/cgi-bin/plot-formula.mpl?expression=CR%5B3%5D=2%282O%5B2%5D%29&x=0003)
NOW, equating the 3 values of the chemical rxn that has combined total of 560cc
![CR[1]+CR[2]+CR[3]=560cc](/cgi-bin/plot-formula.mpl?expression=CR%5B1%5D%2BCR%5B2%5D%2BCR%5B3%5D=560cc&x=0003)
--------------------> working eqn
![O[2]=80cc](/cgi-bin/plot-formula.mpl?expression=O%5B2%5D=80cc&x=0003)
----------------> amount of Oxygen produced by
![CR[2]](/cgi-bin/plot-formula.mpl?expression=CR%5B2%5D&x=0003)
FOR
![CR[1]](/cgi-bin/plot-formula.mpl?expression=CR%5B1%5D&x=0003)
=
![2O[2]=2*80=160cc](/cgi-bin/plot-formula.mpl?expression=2O%5B2%5D=2%2A80=160cc&x=0003)
FOR
![CR[3]](/cgi-bin/plot-formula.mpl?expression=CR%5B3%5D&x=0003)
=
![2(2O[2])=2(2*80)=2(160)=320cc](/cgi-bin/plot-formula.mpl?expression=2%282O%5B2%5D%29=2%282%2A80%29=2%28160%29=320cc&x=0003)
In doubt? Go back working eqn,

, note: cc= cubic centimeter=

Thank you,
Jojo