# SOLUTION: A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the

Algebra ->  -> SOLUTION: A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the       Log On

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 Click here to see ALL problems on Linear-systems Question 99017: A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the brand that is 25% grape juice was used? What are the steps to determine the answer?Answer by stanbon(60772)   (Show Source): You can put this solution on YOUR website!A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the brand that is 25% grape juice was used? What are the steps to determine the answer? -------------- Comment: grape drink is made up of grape juice and water. You need to keep track of the grape juice or the water in each of the solutions. -------------------- 25% grape juice DATA: Amount = x gallons ; Amt of grape in it is 0.25x gallons ----------------- 75% grape juice DATA: Amount = "7-x" gallons; Amt of grape in it is 0.75(7-x) = 5.25-0.75x gallons ------------------- 35% mixture DATA: Amount = 7 gallons: amt of grape is 0.35*7 = 2.45 gallons ------------------- EQUATION: grape + grape = grape 0.25x + 5.25-0.75x = 2.45 -0.50x = -2.8 x = 5.6 gallons (amount of 25% grape juice that must be added) ================ Cheers, Stan H.