# SOLUTION: Richard has 22 coins with a total value of \$4. If the coins are all quarters and dimes, how many of each type of coin does he have?

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 Click here to see ALL problems on Linear-systems Question 98808: Richard has 22 coins with a total value of \$4. If the coins are all quarters and dimes, how many of each type of coin does he have?Answer by ankor@dixie-net.com(16527)   (Show Source): You can put this solution on YOUR website!Richard has 22 coins d + q = 22 d = (22 - q) : with a total value of \$4. .10d + .25q = 4 : If the coins are all quarters and dimes, how many of each type of coin does he have? : Substitute (22-q) for d in the above equation: .10(22-q) + .25q = 4 2.2 - .10a + .25q = 4 -.10q + .25q = 4 - 2.2 .15q = 1.8 q = 1.8/.15 q = 12 quarters : That would give us: 22 - 12 = 10 dimes : : Check solutions .10(10) + .25(12) = 1.00 + 3.00 = 4.00