# SOLUTION: Find an equation of the line having the given slope and containing the given point. m=5, (4,1) The equation of the line in slope intercept form is y= There parts I understand an

Algebra ->  -> SOLUTION: Find an equation of the line having the given slope and containing the given point. m=5, (4,1) The equation of the line in slope intercept form is y= There parts I understand an      Log On

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 Click here to see ALL problems on Linear-systems Question 622748: Find an equation of the line having the given slope and containing the given point. m=5, (4,1) The equation of the line in slope intercept form is y= There parts I understand and some I do not. Here is what I attempted to do to solve the problem m= 5, (4, 1) m=5 and y intercept (4,1) m=5 and b=1 y=4 times x +1 (this is the part I did not understand) y=1Found 2 solutions by Alan3354, ewatrrr:Answer by Alan3354(34679)   (Show Source): You can put this solution on YOUR website!Find an equation of the line having the given slope and containing the given point. m=5, (4,1) ------------------- Use y = mx + b and the point to find b 1 = 5*4 + b b = -19 ----- Then just write it: y = 5x - 19 Answer by ewatrrr(11176)   (Show Source): You can put this solution on YOUR website! ``` Hi, Line with m = 5 and passing thru (4,1) General format for an Equation of a Line is: This Line: m = 5 y = 5x + b | Using Pt(4,1) to solve for b 1 = 20 + b -19 = b y = 5x -19 ```