# SOLUTION: How would you solve these two problems by doing subsitution 2x-3y=9 and 5x+2y=-6

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 Click here to see ALL problems on Linear-systems Question 526550: How would you solve these two problems by doing subsitution 2x-3y=9 and 5x+2y=-6 Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!2x-3y=9........(1) 5x+2y=-6.......(2) Take (1) 2x-3y=9 2x=9+3y 2x/2=(9+3y)/2 x=(9+3y)/2 Put the value of x in (2) 5((9+3y)/2)+2y=-6 Multiply by 2 both sides 2*(5((9+3y)/2)+2*2y=-6*2 5(9+3y)+4y=-12 45+15y+4y=-12 19y=-12-45 19y=-57 19y/19=-57/19 y=-3 Put the value of y in (1) 2x-3y=9 2x-3(-3)=9 2x+9=9 2x=9-9 2x=0 2x/2=0/2 x=0 x,y=0,-3 Check ===== Put the value of x and y in (1) 2x-3y=9 2(0)-3(-3)=9 9=9 Put the value of x and y in (2) 5x+2y=-6 5(0)+2(-3)=-6 -6=-6