# SOLUTION: I need some help with a math question. solve the linear system. 3x-2y= -19,2y= 2x+16

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 Question 253107: I need some help with a math question. solve the linear system. 3x-2y= -19,2y= 2x+16 Found 2 solutions by palanisamy, jim_thompson5910:Answer by palanisamy(496)   (Show Source): You can put this solution on YOUR website!The given equations are, 3x-2y= -19 ...(1) 2y= 2x+16 ...(2) Sustituting in (1), we get 3x-(2x+16) = -19 3x-2x-16 = -19 x = -19+16 x = -3 Put x=-3 in(1). 3*(-3)-2y =-19 -9-2y = -19 -2y = -19+9 y = (-10)/(-2) y = 5 Therefore the solution is x = -3 and y = 5 Answer by jim_thompson5910(29613)   (Show Source): You can put this solution on YOUR website! Start with the first equation. Plug in . In other words, replace each occurrence of '2y' with '2x+16'. Distribute. Combine like terms on the left side. Add to both sides. Combine like terms on the right side. Go back to the second equation. Plug in Multiply Add Divide both sides by to isolate . Reduce. ============================================ Answer: So the solutions are and giving us the ordered pair (-3,5)