# SOLUTION: Please help me solve... A women has \$7000,part is invested for one year paying 7% interest and the remaining amount in a fund paying 9%. After a year total interest on the 2 inv

Algebra ->  -> SOLUTION: Please help me solve... A women has \$7000,part is invested for one year paying 7% interest and the remaining amount in a fund paying 9%. After a year total interest on the 2 inv      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Mathway solves algebra homework problems with step-by-step help!

 Click here to see ALL problems on Linear-systems Question 192182: Please help me solve... A women has \$7000,part is invested for one year paying 7% interest and the remaining amount in a fund paying 9%. After a year total interest on the 2 investments is \$540. How much is invested at each rate?Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!let amounts invested at 7% and 9% be x and y respectively : x+y=7000...........eq 1 .07x+.09y=540......eq 2 : rewrite eq 1 to x=7000-y and plug this into eq 2 : .07(7000-y)+.09y=540 : 490-.07y+.09y=540 : .02y=50 : y=2500 dollars invested at 9% : x=7000-y=7000-2500=4500 dollars invested at 7%