Questions on Algebra: Systems of Linear Equations answered by real tutors!

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Question 168735: solve using any methord
x/3-y/2=3
x/2+y/3=7/3
: solve using any methord
x/3-y/2=3
x/2+y/3=7/3

Answer by jim_thompson5910(9921) About Me  (Show Source):
You can put this solution on YOUR website!

x/3-y/2=3 Start with the first equation.


6(x/cross(3))-6(y/cross(2))=6(3) Multiply EVERY term by the LCD 6 to clear the fractions.


2x-3y=18 Multiply and simplify


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x/2+y/3=7/3 Move onto the second equation.


6(x/cross(2))+6(y/cross(3))=6(7/cross(3)) Multiply EVERY term by the LCD 6 to clear the fractions.


3x+2y=14 Multiply and simplify


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So we have the system of equations:

system(2x-3y=18,3x+2y=14)


2(2x-3y)=2(18) Multiply the both sides of the first equation by 2.


4x-6y=36 Distribute and multiply.


3(3x+2y)=3(14) Multiply the both sides of the second equation by 3.


9x+6y=42 Distribute and multiply.


So we have the new system of equations:
system(4x-6y=36,9x+6y=42)


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


(4x-6y)+(9x+6y)=(36)+(42)


(4x+9x)+(-6y+6y)=36+42 Group like terms.


13x+0y=78 Combine like terms. Notice how the y terms cancel out.


13x=78 Simplify.


x=(78)/(13) Divide both sides by 13 to isolate x.


x=6 Reduce.


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4x-6y=36 Now go back to the first equation.


4(6)-6y=36 Plug in x=6.


24-6y=36 Multiply.


-6y=36-24 Subtract 24 from both sides.


-6y=12 Combine like terms on the right side.


y=(12)/(-6) Divide both sides by -6 to isolate y.


y=-2 Reduce.


So our answer is x=6 and y=-2.


Which form the ordered pair .