# SOLUTION: Find the equation of the line parallel passing through 3x+y=7. x=2;y=1 3/4

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 Question 148283: Find the equation of the line parallel passing through 3x+y=7. x=2;y=1 3/4Answer by nerdybill(7090)   (Show Source): You can put this solution on YOUR website!Find the equation of the line parallel passing through 3x+y=7. x=2;y=1 3/4 . Begin by finding the slope of: 3x+y=7 Do this by manipulating the above until it is in the form of: y = mx + b . 3x+y=7 y = -3x + 7 Here, m=-3 (slope) . Now, we KNOW that parallel lines have to have identical slopes. Therefore, our new equation will have a slope of -3. . The problem also wanted the equation to pass through: x=2;y=1 3/4 or (x,y) = (2,1.75) . Plug the above and the slope into the "slope-intercept" form of the line and solve for b: y = mx + b 1.75 = -3(2) + b 1.75 = -6 + b 7.75 = b . Therefore, the equation of the line is: y = -3x + 7.75