SOLUTION: given 3y<=4,2x+3y<=8, x>=3
do you use 3 inplace of x
if I have to sketch the feasibility region defined by the above restraints how do I if there is only y=4 and y= 2/3. I have t
Algebra.Com
Question 987533: given 3y<=4,2x+3y<=8, x>=3
do you use 3 inplace of x
if I have to sketch the feasibility region defined by the above restraints how do I if there is only y=4 and y= 2/3. I have to label the edges of the region with numbers and the extra with letters as well as find and present the coordinates of the extrema.Assuming x and y are both equal to or greater than zero. Could you work a problem out like that where you show me how to do the linear equations so I can plot it
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
given 3y<=4,2x+3y<=8, x>=3
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The vertical boundary is x = 3 and the area to the right of it.
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Horizontal boundaries are y <= 4/3 and y <= (-2/3)x + (8/3)
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Vertices of solution area:: (3,0.67),(3,0),(4,0)
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Cheers,
Stan H.
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