The system (1) is a consistent system of independent equations if and only if its determinant detis non-zero.
Therefore, if the system (1) is a consistent system of independent equations, then the system (2) is too, because both the systems have the same matrix.
The system (1) is a consistent system of independent equations if and only if two straight lines ax + by = 0 and dx + ey = 0 are distinct and non-parallel
(then they intersect in some unique point).
Therefore, if the system (1) is a consistent system of independent equations, then the system (2) is too, because the system (2) represents
the same straight lines as the system (1).
A system of equations is consistent and independent if and only if the matrix of coefficients is non-singular, which is the same as saying the determinant of the matrix of coefficients is not 0. The two systems have the same coeficient matrices. Thus the answer is yes. The solutions to the first system ax+by=c dx+ey=f isAnd since it is a consistent and independent system, the denominator ae-bd is not 0. The solutions to the second system ax+by=g dx+ey=h is the denominator ae-bd is not 0. So the answer is yes. Edwin