Question 985109: Solve the system of equations:
x+y+z=1
3x-2y-z=5
x+3y+2z=3
(Enter your answer as an ordered triple.) Found 2 solutions by MathLover1, Edwin McCravy:Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website! .......eq.1 .......eq.2 .......eq.3
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.......eq.1 .......eq.2
------------------------------------------add
...............solve for .........eq.1a
.......eq.1....multiply by .......eq.3
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.......eq.1 .......eq.3
---------------------------------------- subtract
.
........solve for ..............eq.2a
from eq.1a and eq.2a we have
......solve for
go to ..............eq.2a, substitute for
go to .......eq.1, substitute for and substitute for
your answer is:(,,)
x+ y+ z = 1
3x-2y- z = 5
x+3y+2z = 3
The solution is: (7/3, 10/3, -14/3)
If you want to know how to solve it,
tell me in the thank-you note form below.
Edwin