SOLUTION: These 3 problems do not come from a book but I really need help with them! If you can solve them as soon as possible, I would greatly appreciate it. Here they are: #1: Write t

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Question 98453: These 3 problems do not come from a book but I really need help with them!
If you can solve them as soon as possible, I would greatly appreciate it.
Here they are:
#1:
Write the equation of the line passing through the points listed below. Write the final answer in the slope-intercept form y = mx + b. If the slope (m) or the y-intercept (b) are not integers, fractions must be used.
(-1, 8); (9, 2)

#2:
A line passes through the origin and the point (-6, 4).
Write the equation of the line that passes through (-6, 4) and is perpendicular to the given line.
Write the final answer in the slope-intercept form y = mx + b.
(The slope and y-intercept must be written as fractions, when needed).

#3:
Write the equation for the line perpendicular to
2x - 5y = 5 and passes through the point (-2, -5).
Enter the variable expression Ax + By separately from the constant term C.
Your response should be given in standard form where A, B and C are the smallest possible integers and A > 0.
Thanks so much.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
These explanations are quite lengthy, so here's a mini table of contents

#1
#2
#3



Go to top

"#1:
Write the equation of the line passing through the points listed below. Write the final answer in the slope-intercept form y = mx + b. If the slope (m) or the y-intercept (b) are not integers, fractions must be used.
(-1, 8); (9, 2)"



First lets find the slope through the points (,) and (,)

Start with the slope formula (note: is the first point (,) and is the second point (,))

Plug in ,,, (these are the coordinates of given points)

Subtract the terms in the numerator to get . Subtract the terms in the denominator to get


Reduce

So the slope is


------------------------------------------------


Now let's use the point-slope formula to find the equation of the line:



------Point-Slope Formula------
where is the slope, and is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)


Rewrite as


Distribute

Multiply and to get

Add to both sides to isolate y

Combine like terms and to get (note: if you need help with combining fractions, check out this solver)


------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line which goes through the points (,) and (,) is:

The equation is now in form (which is slope-intercept form) where the slope is and the y-intercept is

Notice if we graph the equation and plot the points (,) and (,), we get this: (note: if you need help with graphing, check out this solver)

Graph of through the points (,) and (,)

Notice how the two points lie on the line. This graphically verifies our answer.




Go to top

#2:

"A line passes through the origin and the point (-6, 4).
Write the equation of the line that passes through (-6, 4) and is perpendicular to the given line.
Write the final answer in the slope-intercept form y = mx + b.
(The slope and y-intercept must be written as fractions, when needed). "


First find the equation of the line through the points (0,0) (the origin) and (-6,4)


First lets find the slope through the points (,) and (,)

Start with the slope formula (note: is the first point (,) and is the second point (,))

Plug in ,,, (these are the coordinates of given points)

Subtract the terms in the numerator to get . Subtract the terms in the denominator to get


Reduce

So the slope is


------------------------------------------------


Now let's use the point-slope formula to find the equation of the line:



------Point-Slope Formula------
where is the slope, and is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)


Distribute

Multiply and to get . Now reduce to get

Add to both sides to isolate y

Combine like terms and to get
------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line which goes through the points (,) and (,) is:

The equation is now in form (which is slope-intercept form) where the slope is and the y-intercept is

Notice if we graph the equation and plot the points (,) and (,), we get this: (note: if you need help with graphing, check out this
solver)

Graph of through the points (,) and (,)

Notice how the two points lie on the line. This graphically verifies our answer.

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of , you can find the perpendicular slope by this formula:

where is the perpendicular slope


So plug in the given slope to find the perpendicular slope



When you divide fractions, you multiply the first fraction (which is really ) by the reciprocal of the second



Multiply the fractions.


So the perpendicular slope is



So now we know the slope of the unknown line is (its the negative reciprocal of from the line ). Also since the unknown line goes through (-6,4), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

where m is the slope and (,) is the given point



Plug in , , and



Distribute



Multiply



Add to both sides to isolate y

Make into equivalent fractions with equal denominators



Combine the fractions



Reduce any fractions

So the equation of the line that is perpendicular to and goes through (,) is


So here are the graphs of the equations and




graph of the given equation (red) and graph of the line (green) that is perpendicular to the given graph and goes through (,)










Go to top

#3


"Write the equation for the line perpendicular to
2x - 5y = 5 and passes through the point (-2, -5).
Enter the variable expression Ax + By separately from the constant term C.
Your response should be given in standard form where A, B and C are the smallest possible integers and A > 0.

First convert 2x - 5y = 5 to slope intercept form


Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


Start with the given equation


Subtract 2x from both sides


Simplify


Divide both sides by -5 to isolate y


Break up the fraction on the right hand side


Reduce and simplify


The original equation (standard form) is equivalent to (slope-intercept form)


The equation is in the form where is the slope and is the y intercept.






Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of , you can find the perpendicular slope by this formula:

where is the perpendicular slope


So plug in the given slope to find the perpendicular slope



When you divide fractions, you multiply the first fraction (which is really ) by the reciprocal of the second



Multiply the fractions.


So the perpendicular slope is



So now we know the slope of the unknown line is (its the negative reciprocal of from the line ). Also since the unknown line goes through (-2,-5), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

where m is the slope and (,) is the given point



Plug in , , and



Distribute



Multiply



Subtract from both sides to isolate y

Make into equivalent fractions with equal denominators



Combine the fractions



Reduce any fractions

So the equation of the line that is perpendicular to and goes through (,) is


So here are the graphs of the equations and




graph of the given equation (red) and graph of the line (green) that is perpendicular to the given graph and goes through (,)






Now convert back to standard form


Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from slope-intercept form (y = mx+b) to standard form (Ax+By = C)


Start with the given equation


Multiply both sides by the LCD 2


Distribute and multiply


Add 5x to both sides


Simplify


The original equation (slope-intercept form) is equivalent to (standard form where A > 0)


The equation is in the form where , and








If you have any further questions, feel free to ask.

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