The question:
Two fractions have denominators 3 and 4 and their sum is 17/12. If the numerators are switched, the sum is 3/2. Set up a linear system and solve it using elimination to determine the two numerators.
My comments:
I tried to work out this problem starting by making my two equations to try and solve the problem. I started with x/3 + y/3 = 17/12 and y/3 + x/4 = 3/2. From there I tried to do multiple different things but they all ended with a weird answer. How do I correctly solve this problem?
You started off correctly, with the exception that you should have: , and not in the first equation
4x + 3y = 17 -------- Multiplying by LCD, 12 ------- eq (i)
4y + 3x = 18 --------- Multiplying by LCD, 12
3x + 4y = 18 --------- eq (ii)
- 12x - 9y = - 51 ---------- Multiplying eq (i) by - 3 ------ eq (iii)
12x + 16y = 72 ---------- Multiplying eq (ii) by 4 ------- eq (iv)
7y = 21 ---------- Adding eqs (iv) & (iii)
y = , or y = 3
x = 2
Original fractions: